# Quantitative Aptitude Question and Answer [Set-3]

**1**. After division of a number successively by 3, 4, and 7, the remainders obtained are 2, 1 and 4 respectively. What will be the remainder if 84 divide the same number?

**Answer** – **53**

**After division of a number successively by 3, 4, and 7, the remainders obtained are 2, 1 and 4 respectively. If 84 divide the same number the remainder will be 53.**

**1**. After division of a number successively by 3, 4, and 7, the remainders obtained are 2, 1 and 4 respectively. What will be the remainder if 84 divide the same number?

**Answer** – **53**

**After division of a number successively by 3, 4, and 7, the remainders obtained are 2, 1 and 4 respectively. If 84 divide the same number the remainder will be 53.**

**2**. When 2^{256} is divided by 17 the remainder would be?

**Answer** – **1**

**When 2**^{256}is divided by 17 the remainder would be 1.

**2**. When 2^{256} is divided by 17 the remainder would be?

**Answer** – **1**

**When 2**^{256}is divided by 17 the remainder would be 1.

**3**. 12^{55}/3^{11 }+ 8^{48}/16^{18 }will give the digit at units place as?

**Answer** – **0**

**12**^{55}/3^{11 }+ 8^{48}/16^{18 }will give the digit at units place as 0.

**3**. 12^{55}/3^{11 }+ 8^{48}/16^{18 }will give the digit at units place as?

**Answer** – **0**

**12**^{55}/3^{11 }+ 8^{48}/16^{18 }will give the digit at units place as 0.

**4**. What are the last two digits of 7^{2008}?

**Answer** – **0 & 1**

**0 & 1 are the last two digits of 7**^{2008}.

**4**. What are the last two digits of 7^{2008}?

**Answer** – **0 & 1**

**0 & 1 are the last two digits of 7**^{2008}.

**5**. Let b be a positive integer and a=b^{2}-b. If b ≥ 4, then a^{2}-2a is divisible by:

**Answer** – **24**

**If b is a positive integer and a=b**^{2}-b and if b ≥ 4, then a^{2}-2a is divisible by 24.

**5**. Let b be a positive integer and a=b^{2}-b. If b ≥ 4, then a^{2}-2a is divisible by:

**Answer** – **24**

**If b is a positive integer and a=b**^{2}-b and if b ≥ 4, then a^{2}-2a is divisible by 24.

**6**. Suppose n is an integer such that the sum of digits of n is 2, and 10^{11}≥ n ≥10^{10}. The number of different values of n is:

**Answer** – **11**

**Suppose n is an integer such that the sum of digits of n is 2, and 10**^{11}≥ n ≥10^{10}, The number of different values of n is 11.

**6**. Suppose n is an integer such that the sum of digits of n is 2, and 10^{11}≥ n ≥10^{10}. The number of different values of n is:

**Answer** – **11**

**Suppose n is an integer such that the sum of digits of n is 2, and 10**^{11}≥ n ≥10^{10}, The number of different values of n is 11.

**7**. A child was asked to add first few natural numbers (i.e, 1 + 2 + 3…….) so long as his patience is permitted. As he stopped, he gave the sum as 575. When the teacher declared the result wrong the child discovered he had missed one number in the sequence during addition. The number he missed was?

**Answer** – **20**

**The number he missed was 20.**

**7**. A child was asked to add first few natural numbers (i.e, 1 + 2 + 3…….) so long as his patience is permitted. As he stopped, he gave the sum as 575. When the teacher declared the result wrong the child discovered he had missed one number in the sequence during addition. The number he missed was?

**Answer** – **20**

**The number he missed was 20.**

**8**. Three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. What is the sum of the three numbers?

**Answer** – **47**

**If three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. The sum of the three numbers is 47.**

**8**. Three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. What is the sum of the three numbers?

**Answer** – **47**

**If three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. The sum of the three numbers is 47.**

**9**. A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then (a+b)=?

**Answer** – **10**

**A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11, Then (a+b)= 10.**

**9**. A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then (a+b)=?

**Answer** – **10**

**A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11, Then (a+b)= 10.**

**10**. The digits of a 3-digit number A are written in the reverse order to form another 3-digit number B. If B > A and B – A is perfectly divisible by 7, then which of the following is necessarily true?

**Answer** – **106 < A < 305**

**The digits of a 3-digit number A are written in the reverse order to form another 3-digit number B. If B > A and B – A is perfectly divisible by 7, then 106 < A < 305 is true.**

**10**. The digits of a 3-digit number A are written in the reverse order to form another 3-digit number B. If B > A and B – A is perfectly divisible by 7, then which of the following is necessarily true?

**Answer** – **106 < A < 305**

**The digits of a 3-digit number A are written in the reverse order to form another 3-digit number B. If B > A and B – A is perfectly divisible by 7, then 106 < A < 305 is true.**

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